tag:blogger.com,1999:blog-44876501102125338092024-03-19T04:32:28.350-07:00Face da FísicaSilvio Santanahttp://www.blogger.com/profile/12848809471748027972noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-4487650110212533809.post-73556440483681155892011-12-18T17:57:00.001-08:002011-12-18T17:58:18.111-08:00Questão comentada.<div class="separator" style="clear: both; text-align: center;">
<iframe allowfullscreen='allowfullscreen' webkitallowfullscreen='webkitallowfullscreen' mozallowfullscreen='mozallowfullscreen' width='320' height='266' src='https://www.youtube.com/embed/YNf10Xi0Kro?feature=player_embedded' frameborder='0'></iframe></div>Silvio Santanahttp://www.blogger.com/profile/12848809471748027972noreply@blogger.com1tag:blogger.com,1999:blog-4487650110212533809.post-27244574910734264212011-12-18T15:43:00.000-08:002011-12-18T15:44:24.058-08:00Experimento sobre eletrização dos corpos.<div class="separator" style="clear: both; text-align: center;">
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>01. </b>A unidade de carga elétrica no SI é o coulomb (C). Ele é definido a partir de duas outras unidades básicas do SI: a de corrente elétrica, ou seja, o ampère (A) e a de tempo, o segundo (s). Podemos afirmar que:</span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) C = A <b>. </b>s </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) C = A/s </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) C = s/A </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) C = A <b>. </b>s<sup>2</sup> </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) C = A/s<sup>2</sup> </span><span style="font-size: x-small;"> </span><span style="font-size: x-small;"><span style="color: red;"></span></span></span><span style="font-size: x-small;"><br /></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>02. </b>(UFMG) Um isolante elétrico: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) não pode ser carregado eletricamente; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) não contém elétrons; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) tem de estar no estado sólido; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) tem, necessariamente, resistência elétrica pequena; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) não pode ser metálico. </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>03. </b>(FCC - BA) Considere uma esfera metálica oca, inicialmente com carga elétrica nula. Carregando a esfera com um certo número N de elétrons verifica-se que: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) N elétrons excedentes se distribuem tanto na superfície interna como na externa; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) N elétrons excedentes se distribuem em sus superfície interna; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) N elétrons excedentes se distribuem em sua superfície externa; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) a superfície interna fica carregada com cargas positivas; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) a superfície externa fica carregada com cargas positivas. </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>04. </b>(FCC - BA) Considere duas esferas metálicas idênticas. A carga elétrica de uma é Q e a da outra é -2Q. Colocando-se as duas esferas em contato, a carga elétrica da esfera que estava, no início, carregada positivamente fica igual a: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) 3 Q/2 </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) Q/2 </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) -Q/2 </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) -3Q/2 </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) -Q/4 </span><span style="font-size: x-small;"> </span><span style="font-size: x-small;"><span style="color: red;"></span></span><span style="font-size: x-small;"></span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>05. </b>(UE - PI) Três corpos X, Y e Z estão eletrizados. Se X atrai Y e este repele Z, podemos afirmar que certamente: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) X e Y têm cargas positivas. </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) Y e Z têm cargas negativas. </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) X e Z têm cargas de mesmo sinal. </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) X e Z têm cargas de sinais diferentes. </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) Y e Z têm cargas positivas. </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>06. </b>(FUVEST) Duas pequenas esferas metálicas idênticas, inicialmente neutras, encontram-se suspensas por fios inextensíveis e isolantes. </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;">Um jato de ar perpendicular ao plano da figura é lançado durante certo intervalo de tempo sobre as esferas.</span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;">Observa-se então que ambas as esferas estão fortemente eletrizadas. Quando o sistema alcança novamente o equilíbrio estático, podemos afirmar que as tensões nos fios: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) aumentaram e as esferas se atraem; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) diminuíram e as esferas se repelem; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) aumentaram e as esferas se repelem; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) diminuíram e as esferas se atraem; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) não sofreram alterações. </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>07. </b>(UNESP) <b><span style="color: blue;">Em 1990 transcorreu o cinqüentenário da descoberta dos "chuveiros penetrantes" nos </span></b><b><span style="color: blue;">raios </span></b><span style="color: blue;"><b>cósmicos, uma contribuição da física brasileira que alcançou repercussão internacional.</b> </span> </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;">(<i>O Estado de São Paulo</i>, 21/10/90, p. 30)</span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;">No estudo dos raios cósmicos são observadas partículas chamadas <b>píons</b>. Considere um píon com carga elétrica +e se desintegrando (isto é, se dividindo) em duas outras partículas: um <b>múon</b> com carga elétrica +e e um <b>neutrino</b>. De acordo com o princípio de conservação da carga, o <b>neutrino</b> deverá ter carga elétrica:</span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) +e </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) -e </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) +2e </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) -2e </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) nula </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>08. </b>(UNESP) De acordo com o modelo atômico atual, os prótons e nêutrons não são mais considerados partículas elementares. Eles seriam formados de três partículas ainda menores, os quarks. Admite-se a existência de 12 quarks na natureza, mas só dois tipos formam os prótons e nêutrons, o quark up (u), de carga elétrica positiva, igual a 2/3 do valor da carga do elétron, e o quark down (d), de carga elétrica negativa, igual a 1/3 do valor da carga do elétron. A partir dessas informações, assinale a alternativa que apresenta corretamente a composição do próton e do nêutron: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> <b>próton nêutron</b></span></span> <span style="font-size: x-small;"><span style="font-size: x-small;"> </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) d, d, d u, u, u </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) d, d, u u, u, d </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) d, u, u u, d, d </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) u, u, u d, d, d </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) d, d, d d, d, d </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>09. </b>(PUC) Os corpos eletrizados por atrito, contato e indução ficam carregados respectivamente com cargas de sinais: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) iguais, iguais e iguais; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) iguais, iguais e contrários; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) contrários, contrários e iguais; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) contrários, iguais e iguais; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) contrários, iguais e contrários. </span><span style="font-size: x-small;"> </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"><b>10. </b>(FUND. CARLOS CHAGAS) Um bastão de vidro é atritado em certo tipo de tecido. O bastão, a seguir, é encostado num eletroscópio previamente descarregado, de forma que as folhas do mesmo sofrem uma pequena deflexão. Atrita-se a seguir o bastão novamente com o mesmo tecido, aproximando-o do mesmo eletroscópio, evitando o contato entre ambos. As folhas do eletroscópio deverão: </span></span> </div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> a) manter-se com a mesma deflexão, independente da polaridade da carga do bastão; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> b) abrir-se mais, somente se a carga do bastão for negativa; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> c) abrir-se mais, independentemente da polaridade da carga do bastão; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> d) abrir-se mais, somente se a carga do bastão for positiva; </span></span></div>
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<span style="font-size: x-small;"><span style="font-size: x-small;"> e) fechar-se mais ou abrir-se mais, dependendo da polaridade da carga do bastão.</span></span> <span style="font-size: x-small;"><span style="font-size: x-small;"> </span><span style="font-size: x-small;"><span style="color: red;"></span></span></span></div>
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<tr><td style="text-align: center;"><span style="font-size: x-small;"></span><span style="font-size: x-small;"><span style="font-size: x-small;"><strong>01 </strong>- A</span></span></td><td style="text-align: center;"><strong><span style="font-size: x-small;"><span style="font-size: x-small;">02</span></span></strong><span style="font-size: x-small;"><span style="font-size: x-small;"> - E</span></span></td><td style="text-align: center;"><strong><span style="font-size: x-small;"><span style="font-size: x-small;">03</span></span></strong><span style="font-size: x-small;"><span style="font-size: x-small;"> - C</span></span></td><td style="text-align: center;"><strong><span style="font-size: x-small;"><span style="font-size: x-small;">04</span></span></strong><span style="font-size: x-small;"><span style="font-size: x-small;"> - C</span></span></td><td style="text-align: center;"><strong><span style="font-size: x-small;"><span style="font-size: x-small;">05</span></span></strong><span style="font-size: x-small;"><span style="font-size: x-small;"> - D</span></span></td></tr>
<tr><td style="text-align: center;"><span style="font-size: x-small;"><strong><span style="font-size: x-small;">06</span></strong><span style="font-size: x-small;"> - C </span></span></td><td style="text-align: center;"><strong><span style="font-size: x-small;"><span style="font-size: x-small;">07</span></span></strong><span style="font-size: x-small;"><span style="font-size: x-small;"> - E</span></span></td><td style="text-align: center;"><strong><span style="font-size: x-small;"><span style="font-size: x-small;">08</span></span></strong><span style="font-size: x-small;"><span style="font-size: x-small;"> - C</span></span></td><td style="text-align: center;"><span style="font-size: x-small;"><span style="font-size: x-small;"><strong>09 </strong>- E</span></span></td><td style="text-align: center;"><span style="font-size: x-small;"><span style="font-size: x-small;"><strong>10 </strong>- C</span></span></td></tr>
</tbody></table>Silvio Santanahttp://www.blogger.com/profile/12848809471748027972noreply@blogger.com0tag:blogger.com,1999:blog-4487650110212533809.post-44444990275223411762011-11-19T11:35:00.001-08:002011-11-19T11:46:33.009-08:00Centenário da pesquisa de Maxwell<div style="text-align: center;">
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<span class="Apple-style-span" style="background-color: white;"><b><span class="Apple-style-span" style="color: #330033; font-family: Arial;">James </span><span class="SpellE" style="color: #330033; font-family: Arial; font-size: 16px;">Clerk</span><span class="Apple-style-span" style="color: #330033; font-family: Arial;"> Maxwell (1831-1879) obteve analiticamente as quatro </span><span class="SpellE" style="color: #330033; font-family: Arial; font-size: 16px;">equaçoes</span><span class="Apple-style-span" style="color: #330033; font-family: Arial;"> que descrevem as </span><span class="Apple-style-span" style="color: #330033; font-family: Arial;">relações entre eletricidade e magnetismo anteriormente observadas por </span><span class="SpellE" style="color: #330033; font-family: Arial; font-size: 16px;">Faraday</span><span class="Apple-style-span" style="color: #330033; font-family: Arial;"> e que constituem os fundamentos da teoria eletromagnética. As equações de Maxwell formam a base de toda comunicação moderna: TV, rádio, radar, luz e também raios-X. </span></b></span></div>
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<span class="Apple-style-span" style="background-color: white;"><b><span class="Apple-style-span" style="color: #330033; font-family: Arial;">Curiosidade: Quando Albert Einstein ganhador do prêmio Nobel de Física em 1921 olhou para as equações de Maxwell disse: -Maluco, essas equações parecem ser escritas por deuses... fica a dica!</span></b></span></div>Silvio Santanahttp://www.blogger.com/profile/12848809471748027972noreply@blogger.com0tag:blogger.com,1999:blog-4487650110212533809.post-35997152341112790352011-11-18T16:55:00.000-08:002011-11-18T16:55:38.256-08:00O universo numa casca de noz!!!<div class="separator" style="clear: both; text-align: center;"><object width="320" height="266" class="BLOGGER-youtube-video" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=6,0,40,0" data-thumbnail-src="http://1.gvt0.com/vi/tW1vaT_Z60k/0.jpg"><param name="movie" value="http://www.youtube.com/v/tW1vaT_Z60k&fs=1&source=uds" /><param name="bgcolor" value="#FFFFFF" /><embed width="320" height="266" src="http://www.youtube.com/v/tW1vaT_Z60k&fs=1&source=uds" type="application/x-shockwave-flash"></embed></object></div>Silvio Santanahttp://www.blogger.com/profile/12848809471748027972noreply@blogger.com0